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2012年11月网络工程师考试上午真题【基础知识】(第71-75题) 收藏

【71-75】let us now see how randomization is done when a collision occurs . after a (71), timeisdividedinto discrete slots whose length is equal to the worst-case round-trip propagation timeonether.to accommodate the longest path allowed by ethernet, the slot time has been set to 512bittimes,or 51.2us.
after the first collision, each station waits either 0 or 1 (72) times before trying again.iftwostations collide and each one picks the same random number, they will collide again. afterthesecondcollision, each one picks either 0,1,2 or 3 at random and waits that number of slot times.ifathirdcollision occurs (the probability of this happening is 0.25), then the next time the numberofslotsto wait is chosen at (73) from the interval 0 to 23-1.
in general, after i collisions, a random number between 0 and 2i -1 is chosen, and thatnumberofslots is skipped. however, after ten collisions have been reached, the randomization (74)isfrozenat a maximum of 1023 slots. after 16 collisions, the controller throws in the towel and reportsfailureback to the computer. further recoveries up to (75) layers.

【71】选项 (1.0分)

  • Adatagram
  • Bcollision
  • Cconnection
  • Dservice
暂无

【72】选项 (1.0分)

  • Aslot
  • Bswitch
  • Cprocess
  • Dfire
暂无

【73】选项 (1.0分)

  • Arest
  • Brandom
  • Conce
  • Dodds
暂无

【74】选项 (1.0分)

  • Aunicast
  • Bmulticast
  • Cbroadcast
  • Dinterval
暂无

【75】选项 (1.0分)

  • Alocal
  • Bnext
  • Chigher
  • Dlower
暂无
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